Asked by A
Let U, V, and W be independent standard normal random variables (that is, independent normal random variables, each with mean 0 and variance 1), and let X=3U+4V and Y=U+W. Give a numerical answer for each part below. You may want to refer to the standard normal table.
What is the probability that X≥8?
P(X≥8)=
E[XY]=
var(X+Y)=
What is the probability that X≥8?
P(X≥8)=
E[XY]=
var(X+Y)=
Answers
Answered by
juanpro
heyyy i need a good note
Answered by
RVE
some answers
P(X≥8)= 0.054799
var (X+Y) = 33 ?? (not really sure about this one)
fellow classmate: help us out with E[XY] if you are reading this....Feel free to provide your answer to the whole TEST
P(X≥8)= 0.054799
var (X+Y) = 33 ?? (not really sure about this one)
fellow classmate: help us out with E[XY] if you are reading this....Feel free to provide your answer to the whole TEST
Answered by
RVE
E[XY] = 3
var(X+Y)= 33
checked!!
var(X+Y)= 33
checked!!
Answered by
Anonymous
It is indeed:
1) 0.0548
2) 3
3) 33
1) 0.0548
2) 3
3) 33
Answered by
Mary
1)0.0548
2) 3
3) 33
The answers are Checked are ok!
2) 3
3) 33
The answers are Checked are ok!
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