Asked by mican
                Water enters a horizontal pipe with a rectangular cross section at a speed of 1.00 m/s. The width of the pipe remains constant but the height decreases. 27.3 m from the entrance, the height is half of what it is at the entrance. If the water pressure at the entrance is 2921 Pa, what is the pressure 27.3 m downstream? 
            
            
        Answers
                    Answered by
            bobpursley
            
    use the law of continuity to figure the speed downstram
speeddownstream=speedupstream*areaupstream/areadownstream
where area means cross sectional area.
Now, use Bernoulli's law to figure pressure downstream http://www.4physics.com/phy_demo/Bernoulli/Bernoulli.html
because heights are the same (horizontal), it reduces to
P1 + d*v1^2=P2+ d v2^2
solve for P2
    
speeddownstream=speedupstream*areaupstream/areadownstream
where area means cross sectional area.
Now, use Bernoulli's law to figure pressure downstream http://www.4physics.com/phy_demo/Bernoulli/Bernoulli.html
because heights are the same (horizontal), it reduces to
P1 + d*v1^2=P2+ d v2^2
solve for P2
                    Answered by
            mican
            
    I can not find the value of v^2
    
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