Asked by Ahmed
A horizontal pipe 10cm has asmootion to apipe 5 cm in diameter if the pressure of water in the large pipe is 80000pa and the pressure in the smaller pipe is 60000pa at what rate does water flow through the pipes
Answers
Answered by
Damon
velocity in small pipe is four times velocity in big pipe
p + 1/2 rho v^2 is constant and rho is constant
8*10^4 + .5 rho v^2 = 6*10^4 + .5 rho (16)v^2
density of water = rho is about 10^3 kg/m^3
so
8*10^4 + .5*10^3 v^2 = 6^10^4 +8*10^3 v^2
7.5 *10^3 v^2 = 2*10^4
v^2 = (20/7.5)
solve for v in meters/s in large pipe
then volume flow rate = pi r^2 v
note use meters for radius 0.10
p + 1/2 rho v^2 is constant and rho is constant
8*10^4 + .5 rho v^2 = 6*10^4 + .5 rho (16)v^2
density of water = rho is about 10^3 kg/m^3
so
8*10^4 + .5*10^3 v^2 = 6^10^4 +8*10^3 v^2
7.5 *10^3 v^2 = 2*10^4
v^2 = (20/7.5)
solve for v in meters/s in large pipe
then volume flow rate = pi r^2 v
note use meters for radius 0.10
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