Calculate Kc.

CH_4(g) + H_2O(g) <-> CO(g) + 3H_2(g)
Kp= 7.7 x 10^24 at 298K.

Should I use the formula Kp= Kc(RT)^Deltang
If so I have no idea where to start.

1 answer

What do you mean you don't know where to start. This is just a case of substitute and solve.
7.7E24 = Kc(0.08205*298)^(4-2)
Solve for Kc.
Similar Questions
  1. CH_4 (g) + H_2O (g) --> CO (g) + 3H_2 (g)How many moles of water vapor react to yield 144.84 moles of hydrogen? I am confused on
    1. answers icon 1 answer
  2. Use the equation to answer the question.\[CH_4 + 2 O_2 \rightarrow CO_2 + H_2O\] Which statement describes why this chemical
    1. answers icon 1 answer
  3. 1. Calculate Kp for the reaction below at 298K2𝐢𝑙2(𝑔)+10𝑁𝑂(𝑔)⟷5𝑁2(𝑔)+2𝐢𝑙2𝑂5(𝑔)𝐾𝑝=?
    1. answers icon 3 answers
    1. answers icon 1 answer
more similar questions