Asked by Mely
95.0 mL of H_2O is initially at room temperature (22 degree C). A chilled steel rod at 2 degree C is placed in the water. If the final temperature of the system is 21.3 degree C, what is the mass of the steel bar?
Answers
Answered by
bobpursley
the sum of the heats gained is zero.
masssteel*cs*(21.3-2)+masswater*cw*(21.3-22)=0
solve for masssteel. YOu will have to look up the specific heat cs for steel.
masssteel*cs*(21.3-2)+masswater*cw*(21.3-22)=0
solve for masssteel. YOu will have to look up the specific heat cs for steel.
Answered by
Anonymous
8.814
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