Asked by anna
A ball rebounds to one quarter from which it was dropped. approximate the total vertical distance the ball after being dropped from 3ft above the ground ,until it comes to rest
Answers
Answered by
Reiny
first bounce --- 3 ft
2nd bounce = 2(1/4)(3) = 6(1/4)
3rd bounce = 2(1/4)(3)(1/4) = (6)(1/4)^2
4th bounce = ... = (6)(1/4)^3
....
so we have
3 + 6(1/4) + 6(1/4)^2 + 6(1/4)^3 + ... to infinity
= 3 + 6(1/4) (1 + 1/4 + (1/4)^2 + ...)
from the 2nd term on, we have a geometric series
with a = 1 , r = 1/4
sum of all terms
= 3 + (6/4) S∞
= 3 + (3/2)(1/(1-1/4)
= 3 + (3/2)(4/3)
= 5
2nd bounce = 2(1/4)(3) = 6(1/4)
3rd bounce = 2(1/4)(3)(1/4) = (6)(1/4)^2
4th bounce = ... = (6)(1/4)^3
....
so we have
3 + 6(1/4) + 6(1/4)^2 + 6(1/4)^3 + ... to infinity
= 3 + 6(1/4) (1 + 1/4 + (1/4)^2 + ...)
from the 2nd term on, we have a geometric series
with a = 1 , r = 1/4
sum of all terms
= 3 + (6/4) S∞
= 3 + (3/2)(1/(1-1/4)
= 3 + (3/2)(4/3)
= 5
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