Asked by Kimberly
A ball rebounds 7/8ths as high as it bounced on the previous bounce and is dropped from a height of 8 feet. How high does it bounce on the fourth bounce and how far has it traveled after the fourth bounce?
Answers
Answered by
agrin04
Height after 4th bounce = 8x(7/8)^4
Total = 8 + 8*(7/8)*2 + 8*(7/8)^2*2 + 8*(7/8)^3*2 + 8*(7/8)^4
Total = 8 + 8*(7/8)*2 + 8*(7/8)^2*2 + 8*(7/8)^3*2 + 8*(7/8)^4
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