formula? The concept is the closed container gains no heat from outside, so the sum of the heats gained is zero (one gains, one loses).
Heatgaindlead+heatgainedwater=0
2.85g*clead*(Tf-10.3C)+7.55g*cwater*(Tf-52.3)=0
look up the two specific heats (watch units, your mass is in grams). Solve for Tfinal.
Will someone show me the formula or help me through working this question? Thanks!
A 2.85g lead weight, initially at 10.3 deg C, is submerged in 7.55g of water at 52.3 deg C in an insulated container. what is the final temperature of both substances at thermal equilibrium?
3 answers
Alright thanks! Using what you gave me I got T= 53 degrees, hope that's right!
I don't think so....the water was initially hotter, and putting cold lead in made it hotter? I don't think so. Recheck.
1 answer