Ask a New Question

Asked by doug

determine vertex, focus and directrix of parabola. then graph the parabola.

first equation:
y^2 -2x-8=0

second equation:
y^2 -4y -12x= 8

please show your work!
17 years ago

Answers

Answered by drwls
Duplicate post; already answered
17 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2... determine vertex, focus and directrix of parabola. then graph the parabola. second equation:... Find the vertex, focus, and axis of symmetry of the parabola x^2-10x-8y+29 = 0. ==> I do it over... focus (2,3) Vertex (1,-2) Wha is a vertex, a focus, an eccentricity, and a latus rectum Vertex (3,2) focus(-3,2) How do I find vertex, focus and directrix for the following functions? y^2−16y=12x−8^2 x^2+16x... Find the vertex, focus, and directrix of the parabola. x= 1/40 y^2 Determine the​ vertex, focus, and directrix for the following parabola. y=5(x-1)^2-10 What are the vertex, focus, and directrix of the parabola with equation y=x2−6x+15 ?(1 point) Respon...
Submit Your Answer

Question

determine vertex, focus and directrix of parabola. then graph the parabola.

first equation:
y^2 -2x-8=0

second equation:
y^2 -4y -12x= 8

please show your work!

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use