Asked by doug
determine vertex, focus and directrix of parabola. then graph the parabola.
second equation:
y^2 -4y -12x= 8
Please help me this is do 2day bc i forget to turn it in to my teacher
second equation:
y^2 -4y -12x= 8
Please help me this is do 2day bc i forget to turn it in to my teacher
Answers
Answered by
Damon
12 x + 8 = y^2 - 4 y
add 4 to both sides
12 x + 12 = y^2 - 4 y + 4
so
(y-2)^2 = 12 (x+1) = 4*3 (x+1)
opens right
vertex at (-1,2)
focus to vertex = 3 so focus at (2,2)
directrix to vertex = 3 so directrix at x = -4
add 4 to both sides
12 x + 12 = y^2 - 4 y + 4
so
(y-2)^2 = 12 (x+1) = 4*3 (x+1)
opens right
vertex at (-1,2)
focus to vertex = 3 so focus at (2,2)
directrix to vertex = 3 so directrix at x = -4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.