Question
determine vertex, focus and directrix of parabola. then graph the parabola.
second equation:
y^2 -4y -12x= 8
Please help me this is do 2day bc i forget to turn it in to my teacher
second equation:
y^2 -4y -12x= 8
Please help me this is do 2day bc i forget to turn it in to my teacher
Answers
Damon
12 x + 8 = y^2 - 4 y
add 4 to both sides
12 x + 12 = y^2 - 4 y + 4
so
(y-2)^2 = 12 (x+1) = 4*3 (x+1)
opens right
vertex at (-1,2)
focus to vertex = 3 so focus at (2,2)
directrix to vertex = 3 so directrix at x = -4
add 4 to both sides
12 x + 12 = y^2 - 4 y + 4
so
(y-2)^2 = 12 (x+1) = 4*3 (x+1)
opens right
vertex at (-1,2)
focus to vertex = 3 so focus at (2,2)
directrix to vertex = 3 so directrix at x = -4