Question

A bomb of mass M at rest explodes into three pieces in the ratio 1 : 1 : 2. The
smaller ones are thrown off in perpendicular directions with velocities 3 ms−1
and 4 ms−1. What is the velocity of the third piece after the explosion?
you need v such that

3i + 4j + 2(xi+yj) = 0
3+2x = 0
4+2y = 0

v = -3/2 i -2j
now just get the magnitude and direction.

Related Questions

A vessel at rest explodes breaking into three pieces. Two pieces, having equal mass fly off perpendi... A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the... A cherry bomb explodes into three pieces of equal mass. One piece has an initial velocity of 12m/sx^... An object initially at rest on a horizontal OX axis explodes into two pieces . One piece moves just...