Asked by Thousif
A bomb of mass 6 kg initially at rest explodes in to three identical fragments. One
of the fragments moves with a velocity of10 3 / im s , another fragment moves with
a velocity if 10 j m/s, then the third fragment moves with a velocity of magnitude.
of the fragments moves with a velocity of10 3 / im s , another fragment moves with
a velocity if 10 j m/s, then the third fragment moves with a velocity of magnitude.
Answers
Answered by
bobpursley
momentum is conserved. so
initial momentum is zero. So
2*V1+2*V2+2*V3=0
you are given v1, v2. so add them. Then if their sum is L i+Mj, then v3 must be -Li-Mj m/s
and magnitude is sqrt(L^2+M^2)
initial momentum is zero. So
2*V1+2*V2+2*V3=0
you are given v1, v2. so add them. Then if their sum is L i+Mj, then v3 must be -Li-Mj m/s
and magnitude is sqrt(L^2+M^2)
Answered by
Thousif
It's wrong
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