Asked by jennifer
I am having trouble doing this problem. I know how to do indefinate integrals, but I don't know how to do definate integrals. Can you show me how to do this.
Evaluate
5
(x^3-2x)dx
2
Evaluate
5
(x^3-2x)dx
2
Answers
Answered by
drwls
To get the definite integral subtract the value of the indefinite integral at x=2 from the value at x=5. The arbitrary cnstant c will cancel out.
The indefinite integral is x^4/4 - x^2 + C.
The definite integral is
(625/4) - 25 -[16/4 - 4].
The indefinite integral is x^4/4 - x^2 + C.
The definite integral is
(625/4) - 25 -[16/4 - 4].
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