Read "single layer reflection coatings" at
http://en.wikipedia.org/wiki/Anti-reflective_coating#Single-layer_interference_coatings
You need 1/4 wavelength thickness at a refractive index of 1.32
At 531 nm and index 1.32, the wavelength of light is 531/1.32 = 412 nm
The coating thickness should be 1/4 of that
So I'm having some trouble with this problem.. Is there an equation or is it just a ratio? I'm having so many problems with this one!
THANKS!
What is the minimum thickness of coating which should be placed on a lens in order to minimize reflection of 531 nm light? The index of refraction of the coating material is 1.32 and the index of the glass is 1.57.
2 answers
that's what i thought, too. but it's not.
2n(material)t= m*(wavelength/2)
going from a medium with higher n to lower n, you divide the wavelength by 2.
thanks for the help, though. i eventually figured it out!
2n(material)t= m*(wavelength/2)
going from a medium with higher n to lower n, you divide the wavelength by 2.
thanks for the help, though. i eventually figured it out!
2 answers