Question

The Ksp of tin(II) hydroxide, Sn(OH)2, is 5.45 × 10-27. Calculate the solubility of this compound in g/L.

Answer 1

............Sn(OH)2 ==> Sn^2+ + 2OH^-
I............solid.......0........0
C............solid.......x........2x
E............solid.......x........2x

Ksp = (Sn^2+)(OH^-)^2
5.45E-27 = (x)(2x)^2
Solve for x = solubility in mols/L.
Then grams = mols x molar mass

Answer 2

thank you

Answer 3

1.695*10^-7

Answer 4

heather is incorrect

Answer 5

how is heather incorrect?

Answer 6

Heather is correct

Answer 7

Heather is correct. Atta girl Heather. You da real mvp

Answer 8

Heather sucks.

Answer 9

The answer is 1.10861×10^-9 in sapling. Heather truly does suck.

Answer 10

Poor Heather she was only trying. LOL!

Answer 11

Heather is correct, even on sapling. thank you heather, nicely done on the math. the rest of you who say she isn't need to check yourselves

Answer 12

the correct answer is 1.10861*10^-9 on sapling.
Heather sucks.

Answer 13

heather is right

Answer 14

heather played u, its 1.108*10^-9

Answer 15

heather is correct ya'll

Answer 16

she right, you'll crazy just say thanks for the answer

Answer 17

heather could be right......

Answer 18

how can u be so sure, it all depends on what their definition of RIGHT is....

Answer 19

Heather is wrong. I put her answer in sapling and it said, guess what, wrong! I put the sapling answer in and guess what, right! That means heather is wrong.

Answer 20

I don't know what's going on here, I just need some answers xD

Answer 21

Heather is so wrong it's not even funny I don't know how she even got her number just use a calculator.

Answer 22

yall buggin heather's right the problem says the answer is in g/L...jus convert foo