Asked by Anonymous

A 49.5-kg skater is traveling due east at a speed of 2.88 m/s. A 72.5-kg skater is moving due south at a speed of 6.82 m/s. They collide and hold on to each other after the collision, managing to move off at an angle south of east, with a speed of vf.

(a) Find the angle.

(b) Find the speed vf, assuming that friction can be ignored.

I was able to get part A which is 73.9167 ° , but I am not sure how to do part B or even where to start.
Answered by Damon
well, you must have found the east and south speeds to get the angle from
tan angle = speed south/speed east

then
Vf = sqrt (Vsouth^2 + Veast^2)
Answered by rodney
A 20kg box is pulled by a horizontal wire on a circle on rough horizontal for which the coefficient on the kinetic is 0.350.calculate the work down by friction during one complete circle trip if the radiudis 3m.
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