Asked by chris
A 56.0-kg skater is traveling due east at a speed of 2.80 m/s. A 77.0-kg skater is moving due south at a speed of 4.40 m/s. They collide and hold on to each other after the collision, managing to move off at an angle south of east, with a speed of vf. Find (a) the angle and (b) the speed vf, assuming that friction can be ignored.
Answers
Answered by
bobpursley
The momentum is conserved. Therefore the final momentum has E and S as before.
Momentum E=56*2.8
momentum S=4.4*77
Use these to get the angle
arctanTheta=MomentumS/momentumE
where theta is the angle S of E.
Momentum E=56*2.8
momentum S=4.4*77
Use these to get the angle
arctanTheta=MomentumS/momentumE
where theta is the angle S of E.
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