Asked by ryan
Find the area of the region under the curve y = 12 e ^{3 x} between x = -2.6 to x =2.6
Answers
Answered by
Steve
what's the trouble? Straightforward integration:
a = ∫[-2.6,2.6] 12e^(3x) dx
= 4e^3x [2.6,-2.6]
= 9762.41
a = ∫[-2.6,2.6] 12e^(3x) dx
= 4e^3x [2.6,-2.6]
= 9762.41
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