Asked by Yarielis
You are at standing at a window in the University tower that is 42.0 meter above the ground. Your physics professor (who is 2.12 m tall) is walking on the ground below, approaching to tower at a speed of 1.12 m/s. You are holding an egg, which you would like to drop on your professor's head. If you drop the egg from rest, how far in advance of the tower should your professor be (in distance) at the instant of release such that the egg hits him directly on the head as he passes below the window?
Answers
Answered by
Damon
How long to drop 42 - 2.12 = 39.88 meters?
h = Hi + Vi t + (1/2) a t^2
0 = 39.88 + 0 - 4.9 t^2
t^2 = 39.88/4.9
so
t = 2.85 seconds
how far does he walk in 2.85 seconds?
d = 1.12 * 2.85 = 3.2 meters
h = Hi + Vi t + (1/2) a t^2
0 = 39.88 + 0 - 4.9 t^2
t^2 = 39.88/4.9
so
t = 2.85 seconds
how far does he walk in 2.85 seconds?
d = 1.12 * 2.85 = 3.2 meters
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.