Asked by Tator
6.52 g of oxygen gas reacts with some amount of iron, and 11.50 g of Fe2O3 are formed. What was the amount of iron that reacted with the oxygen?
Answers
Answered by
DrBob222
4Fe + 3O2 ==> 2Fe2O3
mols Fe2O3 = grams/molar mass
Using the coefficients in the balanced equation, convert mols Fe2O3 to mols
Fe in the equation.
You want grams Fe? Convert mols Fe to g. g = mols Fe x atomic mass Fe.
Note that the grams 6.52 O2 is not relevant.
mols Fe2O3 = grams/molar mass
Using the coefficients in the balanced equation, convert mols Fe2O3 to mols
Fe in the equation.
You want grams Fe? Convert mols Fe to g. g = mols Fe x atomic mass Fe.
Note that the grams 6.52 O2 is not relevant.
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