Asked by Anonymous
64g of oxygen reacts completely with methane gas to form 44g of carbon dioxide gas and 36 g of water vapour. Calculate the amount of methane that takes part in the reaction .
Answers
Answered by
bobpursley
CH4+ 2O2 >>> 2H2O + CO2
so for each two moles of Oxyen, you use one mole of CH4 and it yields 2moles H2O + one mole of CO2
YOu got 44 grams of CO2, which is one mole.
You got 36 grams of H2O, which is 2 moles
So you needed two moles of oxygen, or 64 grams, which you used.
So you must have used one mole of CH4, which is 16 grams.
so for each two moles of Oxyen, you use one mole of CH4 and it yields 2moles H2O + one mole of CO2
YOu got 44 grams of CO2, which is one mole.
You got 36 grams of H2O, which is 2 moles
So you needed two moles of oxygen, or 64 grams, which you used.
So you must have used one mole of CH4, which is 16 grams.
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