Asked by Sally
Fluorine reacts with oxygen to yield oxygen difluoride.
2 F2(g) + O2(g)<--> 2 OF2(g)
What is the value of K if the following concentrations are found at equilibrium: [O2]= 0.200 mol/L, [F2]=0.0100 mol/L, and [OF2]=0.0633 mol/L
2 F2(g) + O2(g)<--> 2 OF2(g)
What is the value of K if the following concentrations are found at equilibrium: [O2]= 0.200 mol/L, [F2]=0.0100 mol/L, and [OF2]=0.0633 mol/L
Answers
Answered by
DrBob222
Kc = (OF2)^2/(F2)^2(O2)
Substitute and solve.
Substitute and solve.
Answered by
Sally
I get 8.01 for an answer, but webassign says it's wrong.
[0.0633]^2/[o.0100]^2[o.200]=8.01378
[0.0633]^2/[o.0100]^2[o.200]=8.01378
Answered by
DrBob222
You have it set up right but your must be punching the wrong buttons on the calculator. I get 200.344 which must be rounded, of course.
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