Asked by shanise
the line passes through the points s(6,6) and T(0,-2) determine the gradient of the line
the equation of the line
the midpoint of the line segment,TS
the length of the line segment,TS
the equation of the line
the midpoint of the line segment,TS
the length of the line segment,TS
Answers
Answered by
Reiny
gradient
= slope
= (6-(-2))/(6-0)
= 8/6 = 4/3
since (0,-2) is the y-intercept or the b of the y = mx + b notation, we can simply write
y = (4/3) - 2
surely you have 2 little formulas in your text or your notebook to find the midpoint and the length.
Let me know what you get.
= slope
= (6-(-2))/(6-0)
= 8/6 = 4/3
since (0,-2) is the y-intercept or the b of the y = mx + b notation, we can simply write
y = (4/3) - 2
surely you have 2 little formulas in your text or your notebook to find the midpoint and the length.
Let me know what you get.
Answered by
shanise
mid point
y2+y1/2
-2+6/2
4/2
=2
x2-x1/2
0-6/2
-6/2
=-3
y2+y1/2
-2+6/2
4/2
=2
x2-x1/2
0-6/2
-6/2
=-3
Answered by
Reiny
Ohh dear!
midpoint is a "point" so it must look like ( ? , ? )
your method should be
the x of the midpoint is (6+0)/2= 3
the y of the midpoint is (6-2)/2 = 2
so the midpoint is (3,2)
(notice that in effect we are taking the average of the x's and the average of the y's)
length
= √(6-0)^2 + (6-(-2))^2)
= √(36 +64)
= √100
= 10
midpoint is a "point" so it must look like ( ? , ? )
your method should be
the x of the midpoint is (6+0)/2= 3
the y of the midpoint is (6-2)/2 = 2
so the midpoint is (3,2)
(notice that in effect we are taking the average of the x's and the average of the y's)
length
= √(6-0)^2 + (6-(-2))^2)
= √(36 +64)
= √100
= 10
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