Asked by sonaa
car initially moving at 19 m/s brakes with an acceleration of 2.97 m/s2. How long will it take for the car to stop in seconds?
Answers
Answered by
Damon
v = Vi + a t
a is negative (deacceleration)
0 = 19 - 2.97 t
t = 6.4 seconds
a is negative (deacceleration)
0 = 19 - 2.97 t
t = 6.4 seconds
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