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car initially moving at 19 m/s brakes with an acceleration of 2.97 m/s2. How long will it take for the car to stop in seconds?
11 years ago

Answers

Damon
v = Vi + a t
a is negative (deacceleration)

0 = 19 - 2.97 t
t = 6.4 seconds
11 years ago

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