Question

Initially, a particle is moving at 4.00 m/s at an angle of 33.5 degrees above the horizontal. Two seconds later, its velocity is 6.45 m/s at an angle of 60.0 degrees below the horizontal. What was the particle's average acceleration during these 2.00 seconds? Enter the x and y components of the average acceleration separated by comma.

Aavgx= ?
Aavgy= ?

I don't have a clue where to start.

Answer 1

never mnind, i just saw similar posts to my question