Question

The initial velocity of a 1.55 kg block sliding down a frictionless inclined plane is found to be 1.27 m/s. Then 1.07 s later, it has a velocity of 5.37 m/s.
What is the angle of the plane with respect to the horizontal?

Answer 1

It's the same question, just put your data..

The initial velocity of a 2.56 kg block sliding down a frictionless inclined plane is found to be 1.13 m/s. Then 1.08 s later, it has a velocity of 3.99 m/s.What is the angle of the plane with respect to the horizontal?

Acceleration = a = (3.99-1.13)/1.08
= 2.648 m/s^2

Force along the plane = M*g sinA = M*a

sinA = a/g = 0.270

A = sin^-1(0.270)= 15.7 degrees