Asked by Anonymous
The initial velocity of a 4.0-kg box is 11 m/s, due west. After the box slides 4.0 m horizontally, its speed is 1.5 m/s. Determine the magnitude and the direction of the non-conservative force acting on the box as it slides
Answers
Answered by
drwls
Work done against friction (F * X) equals loss of kinetic energy.
Solve for F
V = 4.0 meters
Solve for F
V = 4.0 meters
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