A current of 2.10A flows in a wire. How many electrons are flowing past any point in the wire per second?

Question

N=________________________ electrons/s

Answer 1

well, since 1A = 1 Coulomb/sec, just multiply the current (A) by the number of electrons in a Coulomb.

Answer 2

so it would be
N= (2.10A) x (1.602176487×10^−19 C)
= 3.3642 x 10 ^19

Thank you very much Steve!