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Questions (1)
A current of 2.10A flows in a wire. How many electrons are flowing past any point in the wire per second?
N=_____________________
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Answers (3)
Judgement kazzy is correct! Just took it!
583
so it would be N= (2.10A) x (1.602176487×10^−19 C) = 3.3642 x 10 ^19 Thank you very much Steve!
