a. d = Vo*t + 0.5a*t^2 = 11.5 m.
0 + 0.5a*5.4^2 = 11.5
14.58a = 11.5
a = 0.789 m/s^2
m = F/a = 73/0.789 = 92.55 kg.
b. V=Vo + a*t = 0 + 0.789*5.4=4.26 m/s.
d = Vo*t = 4.26 m/s * 4.20s = 17.89 m.
A dockworker applies a constant horizontal force of 73.0N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 11.5m in a time 5.40s .
a.) What is the mass of the block?
b.)If the worker stops pushing at the end of 5.40s , how far does the block move in the next 4.20s ?
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2 answers