Asked by Michael
A dockworker applies a constant horizontal force of 82.0 to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 12.5 in a time 4.60 .
Answers
Answered by
Damon
I suppose you want the mass?
82 = m a
d = (1/2)a t^2
12.5 = .5 a (4.6)^2
a = 1.18
so
82 = m (1.18)
m = 69.4 kg
I have to assume that you are using SI units. Please in the future type the entire problem including units and the question itself.
82 = m a
d = (1/2)a t^2
12.5 = .5 a (4.6)^2
a = 1.18
so
82 = m (1.18)
m = 69.4 kg
I have to assume that you are using SI units. Please in the future type the entire problem including units and the question itself.