Question

a dockworker applies a constant horizontal force of 80 N to a block of ice on a smooth horizontal floor. The friction force is negligible the block start from rest and move 11m in 5 sec what is it mass & if worker stop pushing at 5sec .How for does the block move in 5 ec

Answer 1

d = (1/2) a t^2

11 = (1/2) a (25)

a = .88 m/s^2

so
80 = m (.88)
m = 90.9 kg

v = a t = .88*5 = 4.4 m/s which continues without force
for five seconds so
4.4 * 5 = 22 meters more

Answer 2

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