Asked by Mary
What is sin^2 - cos^2 x/ 1-2cos^2 x, using the identities.
Answers
Answered by
Reiny
cos 2A
= cos^2 A - sin^2 A
or 2cos^2 A - 1
or 1 - 2sin^2 A
so (sin^2 - cos^2 x)/ (1-2cos^2 x)
= -cos 2x / - cos 2x
= +1
= cos^2 A - sin^2 A
or 2cos^2 A - 1
or 1 - 2sin^2 A
so (sin^2 - cos^2 x)/ (1-2cos^2 x)
= -cos 2x / - cos 2x
= +1
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