Asked by Melissa
A commuter backs her car out of her garage with a constant acceleration of 1.20 m/s2.
(a) How long does it take her to reach a speed of 1.60 m/s?
s
(b) If she then brakes to a stop in 0.8 s, what is her (constant) deceleration?
(a) How long does it take her to reach a speed of 1.60 m/s?
s
(b) If she then brakes to a stop in 0.8 s, what is her (constant) deceleration?
Answers
Answered by
Damon
v = a t
1.6 = 1.2 t
t = 1.33 seconds
Vi = 1.60
v = Vi + a t
0 = 1.60 + a * 0.8
a = - 2 m/s^2
1.6 = 1.2 t
t = 1.33 seconds
Vi = 1.60
v = Vi + a t
0 = 1.60 + a * 0.8
a = - 2 m/s^2
Answered by
Daniel from conections academy
i forgot
Answered by
Mary
Are you Daniel Spry?
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