Asked by Sykox
find the points on the curve [(x^2 )+ (y^2) = 18] at which the tangents are parallel to the line x+y = 3
Answers
Answered by
Steve
the line has slope -1
x^2+y^2=18
dy/dx = -x/y
so, we need x = y
x^2+x^2 = 18
x = ±3, so the points are
(-3,-3) and (3,3)
visit wolframalpha.com and enter
plot x^2+y^2=18, x+y = -6, x+y=6, x=3, y=3
x^2+y^2=18
dy/dx = -x/y
so, we need x = y
x^2+x^2 = 18
x = ±3, so the points are
(-3,-3) and (3,3)
visit wolframalpha.com and enter
plot x^2+y^2=18, x+y = -6, x+y=6, x=3, y=3
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