Hint:
1. Use implicit differentiation to find y'.
2. Equate y' to -1 and solve for all possible values of x and y.
I find x=1,y=1 lies on the curve where the tangent is -1.
Check my work.
find all points at the curve x^2y^2+2xy=3 with the slope of the tsngent is -1
1 answer