#1. For H2SO4L:
2NaOH + H2SO4 --> Na2SO4 + 2H2O
moles H2SO4 = M x L = ??
moles NaOH = 2x moles H2SO4 (from the equation).
M NaOH = moles NaOH/L NaOH.
#1. For HCl:
NaOH + HCl ==> NaCl + H2O
moles NaOH = M(from the first part) x L
moles HCl = moles NaOH (from the equation).
M HCl = moles HCl/L HCl
#2.
NaOH + HCl ==> NaCl + H2O
moles HCl = M x L = ??
moles NaOH = moles HCl (from the equation).
M NaOH = moles NaOH/L NaOH
Note: volume of NaOH is determined by subtracting the initial reading from the final reading.
1) You are given solutions of HCl and NaOH and must determine their concentrations. You use 37.0mL of NaOH to titrate 100mL of HCl and 13.6 mL of NaOH to titrate 50.0mL of 0.0782 M H2SO4. Find the unknown concentrations.
Molarity of NaOH and molarity of HCL?
2) Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide solution was standardized by titrating 28.00mL of 0.1598 M standard HCl. The initial buret reading of the sodium hydroxide was 2.54mL, and the final reading was 39.85mL. What is the molarity of the base solution?
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