You don't have the entire problem copies. What you need is the volume of NaOH added in your titration but here is what you do.
mols NaOH = M x L. That's 0.75M x L you used in the titrant.
mols HCl = mols NaOH from above.
Then M HCl = mols HCl/L HCl. The problem says L HCl = 0.1 (i.e., 100 ml).
(7 points)
1. The reaction that you just witnessed in while doing your titration was: HCl + NaOH H2O + NaCl. This equation is balanced. Your unknown solutions contained HCl solutions of unknown concentrations, and your titrant was a 0.75 M solution of NaOH. Use the information from the lab to calculate the concentrations of HCl in your 2 unknown solutions. Assume we have 100 mL of each Unknown solution.
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