1. 8^2 x^2(x+6)^2
=
2. 480 = (w+10)w
1) The first leg of a right triangle is 6 cm longer than its second leg. If the hypotenuse has a length of 8 cm, find the exact lengths of the two legs.
First Leg:
Second Leg:
2) The length of a rectangle is 10 m longer than its width and the area of the rectangle is 480 m2. Find the exact dimensions of the rectangle.
W =
L =
3 answers
1. x^2 + (x+6)^2 = 8^2
x^2 + x^2 + 12x + 36 - 64 = 0
2x^2 + 12x - 28=0
x^2 + 6x - 14 = 0
x^2 + 6x = 14 , completing the square ....
x^2 + 6x + 9 = 14+9
(x+3)^2 = 23
x+3 = ± √23
x = -3 ± √23
but x has to be positive
so x = √23 - 3
so one leg is √23 - 3 , the other is √23 + 3
#2. solve the equation that kuai gave you
x^2 + x^2 + 12x + 36 - 64 = 0
2x^2 + 12x - 28=0
x^2 + 6x - 14 = 0
x^2 + 6x = 14 , completing the square ....
x^2 + 6x + 9 = 14+9
(x+3)^2 = 23
x+3 = ± √23
x = -3 ± √23
but x has to be positive
so x = √23 - 3
so one leg is √23 - 3 , the other is √23 + 3
#2. solve the equation that kuai gave you
I have no idea dude
1 answer