1)Find the exact solutions to 3x^2=5x-1 using the quadratic formula.
answer=5 plus or minus the square root of 37 over 6
2)Use the discriminant to determine the number and type of roots for the equation 2x^2-7x+9=0
answer=2 complex
3)Identify the vertex,axis of symmetry,and direction of opening for y=1/2(x-8)^2+2
answer=(8,2);x=-8;up
4)Which quadratic function has its vertex at(-2,7)and opens down?
answer=y=(x-2)^2+7
5)Write y=x^2+4x-1 in vertex form
answer=y=(x-2)^2+5
#1, watch your signs
3x^2 - 5x + 1=0
x=(5±√(25-12))/6 = (5±√(13))/6
#2, ok
#3, vertex is ok, but how can the axis of symmetry be x=-8?? Would it not go through the vertex?? So it is x=9 (always the same as the x of the vertex)
#4 yours opens UP
it should be y = -(x-2)^2+5
#5 no, it should be y=(x+2)^2-5
(why don't you expand your answer, it would not work)
0 answers