Asked by Jon
Find the exact solutions to 6x^2+x+4=0 by using the quadratic formula.
x=-b+-sqrtb^2-4ac/2a
-1+-sqrt1^2-4(6)(4)/2(6)
-1+-sqrt-95/12
-1-95/12
-96/12
x= -8
-1+95/12
94/12= 7.8333..
[-8, 7.83](answer)
x=-b+-sqrtb^2-4ac/2a
-1+-sqrt1^2-4(6)(4)/2(6)
-1+-sqrt-95/12
-1-95/12
-96/12
x= -8
-1+95/12
94/12= 7.8333..
[-8, 7.83](answer)
Answers
Answered by
mk-tintin
do u cumplex numbers???
Answered by
Jon
What do you mean?
Answered by
mk-tintin
do u know cumplex numbers???as your sqrt is negative(b²-4ac=-95) you have to use cumplex numbers to solve this equation
Answered by
Jon
no that's the only way I know how to do it.
Answered by
mk-tintin
so 6x²+x+4=0 has no one solution(no one real solution but there are cumplex solution : it's (-1+-isqrt95)/12
Answered by
Doc of MH
since a=6,b=1,c=4
=-B¡¾¡î(B©÷-4AC)/2A
"-1¡¾¡î(1©÷-4(6)(4))/2(6)
"-1¡¾¡î(-95)/12
so the roots are imaginary
"since the square root of "-1" is "I"
(yes the letter "I")
Then your roots are
"(-1+9.74i)/12 and (-1-9.74i)/12
=-B¡¾¡î(B©÷-4AC)/2A
"-1¡¾¡î(1©÷-4(6)(4))/2(6)
"-1¡¾¡î(-95)/12
so the roots are imaginary
"since the square root of "-1" is "I"
(yes the letter "I")
Then your roots are
"(-1+9.74i)/12 and (-1-9.74i)/12
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