#1: (4p-1)-(6p) = (p^2-1)-(4p-1)
#2:
(y+6)/3y = -3
y = -3/5
(z+1)/(y+6) = -3
Now plug in y and solve for z
1. Find all values of p so that 6p, 4p-1, p^2 - 1 will be an arithmetic sequence.
2. The common ration of a geometric sequence is -3. IF the terms of this sequence are 3y, y+6, z+1, ..... respectively, what is the value of z?
1 answer