1. Find all intervals on which the graph of y=(x^2+1)/x^2 is concave upward.

A. (negative infinity, infinity)
B. (negative infinity, -1) U (1, infinity)
C. (negative infinity, 0) U (0, infinity)
D. (1, infinity)
E. none of these
I got C. I found the second derivative and used the interval test.

2. If f(3)=0, f’(3)=6, g(3)=1, g’(3)=1/3, find h’(3) if h(x)=[f(x)] / [g(x)]
A. 18
B. 6
C. -6
D. -2
E. none of these
I got B. I figured out h'(x) in terms of f(x), g(x), f'(x), and g'(x) and plugged in the given numbers.

3. Find all open intervals on which f(x)=x/(x^2+x-2) is decreasing.
A. (negative infinity, infinity)
B. (negative infinity, 0)
C. (negative infinity, -2) U (1, infinity)
D. (negative infinity, -2) U (-2,1) U (1, infinity)
E. none of these
I got C. I found the first derivative and critical numbers. Then I used the interval test.

Thank you for checking my answers.

1 answer

#1 ok

#2
h' = (f'g-fg')/g^2 = (6*1-0*1/3)/1 = 6
So, B is correct

#3
f' = -(x^2+2)/(x^2+x-2)^2
f' < 0 for all x
So, (D) is correct
Similar Questions
  1. 1. Given f(x)=-6/x, choose the correct statementA. The graph of f is concave upward on the interval (negative infinity, 0) B.
    1. answers icon 1 answer
  2. f(x)= x/(1+x)^2c) find the intervals of concavity and the inflection points. My answers: f is concave downward on (- infinity,
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. Let F(x)=int from 0 to x of (t-3)/(t^2+7) dt for -infinity <x< infinity.a. Find the value of x where F attains its minimum
    1. answers icon 0 answers
more similar questions