Asked by Branden
Find all the intervals on which the function is concave upward: f(x)=4x^2-x/x^4
Answers
Answered by
bobpursley
f'=8x+4x^4
f"=8+16x^3
so if f">0, then x^3>1/2 and x>cubrt(1/2)
f"=8+16x^3
so if f">0, then x^3>1/2 and x>cubrt(1/2)
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