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Asked by Branden

Find all the intervals on which the function is concave upward: f(x)=4x^2-x/x^4
14 years ago

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Answered by bobpursley
f'=8x+4x^4
f"=8+16x^3

so if f">0, then x^3>1/2 and x>cubrt(1/2)
14 years ago
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Find all the intervals on which the function is concave upward: f(x)=4x^2-x/x^4

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