Asked by Alex
Find all intervals on which the given expressions are positive.
(x-1)(x+2)
I know the answer is : x<-2, x>1
please show me the steps on how to solve this math problem.
(x-1)(x+2)
I know the answer is : x<-2, x>1
please show me the steps on how to solve this math problem.
Answers
Answered by
Steve
to have the product be positive, either both factors are negative, or both are positive.
Both negative:
x-1 < 0 AND x+2 < 0
x < 1 AND x < -2
==> x < -2
Both positive:
x-1 > 0 AND x+2 > 0
x > 1 AND x > -2
==> x > 1
or, you can consider what you know about polynomials. If there are no repeated roots, then the graph crosses the x-axis at various points. In between those points, the function does not change sign. When crossing the axis, the function changes sign.
So, consider x very large negative. Both factors are negative, so the product is positive. Each time it crosses the x-axis (at one of the roots), it changes sign. So, looking at the number line, and marking + or -, we start way out on the left with +, and change sign at each root:
++++++ -2 ----- 1 +++++++
Repeated roots modify this algorithm some, as the graph may just touch the axis and not change sign.
Both negative:
x-1 < 0 AND x+2 < 0
x < 1 AND x < -2
==> x < -2
Both positive:
x-1 > 0 AND x+2 > 0
x > 1 AND x > -2
==> x > 1
or, you can consider what you know about polynomials. If there are no repeated roots, then the graph crosses the x-axis at various points. In between those points, the function does not change sign. When crossing the axis, the function changes sign.
So, consider x very large negative. Both factors are negative, so the product is positive. Each time it crosses the x-axis (at one of the roots), it changes sign. So, looking at the number line, and marking + or -, we start way out on the left with +, and change sign at each root:
++++++ -2 ----- 1 +++++++
Repeated roots modify this algorithm some, as the graph may just touch the axis and not change sign.
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