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For the reaction Ba(OH)2+2HCLO3 -> Ba(CIO3)2+2H2O calculate the no. of mole of H2O formed .when .01 mole of Ba(OH)2 is treated
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Ammonia gas is passed into water ,yielding a solution of density 0.93 g/cm^3 and containing 18.6% NH3 by wieght .The mass of NH3
2 answers
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when 400g of a 20% sol. by weight was cooled ,50g of solute percipited .the percentage concentration of remaining solution
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Answers (1)
For the reaction Ba(OH)2+2HCLO3 -> Ba(CIO3)2+2H2O calculate the no. of mole of H2O formed .when .01 mole of Ba(OH)2 is treated with 0.0250 moles of HCLO3
