For the reaction Ba(OH)2+2HCLO3 -> Ba(CIO3)2+2H2O calculate the no. of mole of H2O formed .when .01 mole of Ba(OH)2 is treated with 0.0250 moles of HCLO3

Answer 1

0.01 mol Ba(OH)2 will produce 0.02 mole H2O if all of the HClO3 needed is present for the reaction.
0.0250 HClO3 will produce 0.025 mole H2O if all of the Ba(OH)2 needed is present for the reaction.
So which is the limiting reagent? Which amount of H2O will be produced?

Answer 2

0.44