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so CONFUSED!
Questions (4)
Under which condition can you hold your breath longer?
First breathe in as much as you can and hold your breath, and time it.
2 answers
1,271 views
Under which condition can you hold your breath longer?
First breathe in as much as you can and hold your breath, and time it.
2 answers
631 views
How do I integrate this?
constant(1- z/[sqrt (z^2 + constant^2)] i know i can take the constant out so I have constant * integral
3 answers
439 views
I'm having trouble relating Work, with Electric Field, with Kinematics. The question is asking:
How fast and what direction is
1 answer
550 views
Answers (7)
i got it! thats close but not right :)
Always start with Let statements. Let "S" represent the length of one side of the square. Let "T" represent the length of one side of the triangle. Now rewrite your question as equations. A square and an equilateral triangle has the same perimeter. 4S = 3T
There is no table provided... not sure how to answer this. Substitute values of x from the table, and compare the calculated y-value with the table.
Always start with "Let" statements. Let "J" represent the number of quarters Jenna has. Let "T" represent the number of quarters Tony has. Using these variables, phrase your question into algebraic equations. Jenna has 3 x as many as Tony J = 3T Together
That makes sense, that there is enough oxygen to supply the body for a longer time, however, I thought the body senses CO2 more, so after maximal exhalation, the CO2 decreases in blood, and you can hold your breath longer?
is it just integral 1 + integral f(x) and the integral 1 = x?
sorry i meant 1- f(x) 1-, not 1+
