Asked by Joshua
Jenna and Tony need quarters for bus fare. Jenna has 3 x as many as Tony.
Together they have $11.00 in quarters. How many coins does each have?
Together they have $11.00 in quarters. How many coins does each have?
Answers
Answered by
bobpursley
J=3T
J*.25+T*.25=11.00
(3T+T)*.25=11.00
solve for T first.
J*.25+T*.25=11.00
(3T+T)*.25=11.00
solve for T first.
Answered by
so CONFUSED!
Always start with "Let" statements.
Let "J" represent the number of quarters Jenna has.
Let "T" represent the number of quarters Tony has.
Using these variables, phrase your question into algebraic equations.
Jenna has 3 x as many as Tony
J = 3T
Together they have $11.00 in quarters. That's 4 quarters in every dollar, so $11 is 44 quarters.
J + T = 44
Now using those two equations, you can substitute and solve.
I leave that to you :)
Let "J" represent the number of quarters Jenna has.
Let "T" represent the number of quarters Tony has.
Using these variables, phrase your question into algebraic equations.
Jenna has 3 x as many as Tony
J = 3T
Together they have $11.00 in quarters. That's 4 quarters in every dollar, so $11 is 44 quarters.
J + T = 44
Now using those two equations, you can substitute and solve.
I leave that to you :)
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