rickross
This page lists questions and answers that were posted by visitors named rickross.
Questions
The following questions were asked by visitors named rickross.
Consider an insulating sphere with 10 microCoulombs of charge uniformly distributed through its volume. The sphere is surrounded by a conducting spherical shell that has a total charge of -3 microCoulombs. Outside the conucting shell is an insulating shel...
11 years ago
In addition to the Mg nucleus at x = 3 cm, another 3e charge is situated on the y-axis, 3cm away from the origin in the +y direction as shown below: What is the magnitude of the Electric Field halfway between the Magnesium nucleus and the 3e charge on the...
11 years ago
An insulating sphere of mass m and positive charge q is attached to a spring with length h and spring constant ks and is at equilibrium as shown below: An infinitely long wire with positive linear charge density λ is placed a distance l away from the char...
11 years ago
Answers
The following answers were posted by visitors named rickross.
hai bob what the charge enclosed on this formula E=k*chargeenclosed/distance from center. ??? i used 10microC but give wrong ans . and did u got ans for a???? i checked 20microC and give wrong ans
11 years ago
hai why is marked incorrect did u get green check on this question ?? and thx for support
11 years ago
An insulating sphere of mass m and positive charge q is attached to a spring with length h and spring constant ks and is at equilibrium as shown below: An infinitely long wire with positive linear charge density λ is placed a distance l away from the char...
11 years ago
Distance between charges is d=sqrt{3²+3²} =4.24 cm x=d/2 =4.24/2 =2.12 cm =0.0212 m E=kq₁/x²-kq₂/x² = =k12e/x²+k3e/x²=k9e/x²= =9•10⁹•15•1.6•10⁻¹⁹/0.0212²= =4.8•10⁻⁵ N/C try this !!!
11 years ago
any hint how i can solve this What is the magnitude of the net electrostatic force a Boron nucleus would experience at the point halfway between the Magnesium nucleus and the 3e charge on the y axis in N? ???
11 years ago
thank bro !!! but for b)is E(0.05) = k*1e-5/(0.05^2)=3.6e7 C
11 years ago
An insulating sphere of mass m and positive charge q is attached to a spring with length h and spring constant ks and is at equilibrium as shown below: An infinitely long wire with positive linear charge density λ is placed a distance l away from the char...
11 years ago
Hai is check incorrect can u plz check if u write it correct and thx !!!
11 years ago
What is the magnitude of the net electrostatic force a Boron nucleus would experience at the point halfway between the Magnesium nucleus and the 3e charge on the y axis in N?
11 years ago
What is the magnitude of the net electrostatic force a Boron nucleus would experience at the point halfway between the Magnesium nucleus and the 3e charge on the y axis in N?
11 years ago
hai asha for 7) tan(theta)=(E*q)/(m*g) and i not yet done for 6 question if u got correct ans help me ??? also for 5 question if u got it correct help me ???? 7)tan(theta)=(E*q)/(m*g) 6)?? 5)??
11 years ago
hai did u done for 5question What is the magnitude of the net electrostatic force a Boron nucleus would experience at the point halfway between the Magnesium nucleus and the 3e charge on the y axis in N?
11 years ago
hai Unrickross 4th question ans is Distance between charges is d=sqrt{3²+3²} =4.24 cm x=d/2 =4.24/2 =2.12 cm =0.0212 m E=kq₁/x²-kq₂/x² = =k12e/x²+k3e/x²=k9e/x²= =9•10⁹•15•1.6•10⁻¹⁹/0.0212²= =4.8•10⁻⁵ N/C try this !!!
11 years ago
hai Unrickross !!! i need ans for 5th question ??? 5??
11 years ago
unrickross ! first tell me if u got green check on that 4th question better i have to explain !!! so what about 5th question ???
11 years ago
Oh God unrickross i made mistake on my sign but the last ans is correct so it would be Distance between charges is d=sqrt{3²+3²} =4.24 cm x=d/2 =4.24/2 =2.12 cm =0.0212 m E=kq₁/x²+kq₂/x² = =k12e/x²+k3e/x²=k15e/x²= =9•10⁹•15•1.6•10⁻¹⁹/0.0212²= =4.8•10⁻⁵ N/...
11 years ago
hai unrickross THX foR 5QUESTION I got green check !!!
11 years ago
q1 a) F = dp/dt dp = Fdt ∫dp = ∫Fdt p_f - p_i = ∫βt²dt p_f - 0 = (β/3)(t_f)^3 - (β/3)(t_i)^3 no idea for part b) and c) any help ???
11 years ago
that's is grt formula i got it correct using that formula! hai Greco help for q8?
11 years ago
hai damon this integral is correct for part b F = 1.2 t^2 - 10(3)(.2) = 1.2t^2-6 integral F dt = 1.2 t^2/3 - 6 t ????
11 years ago
k thanks did u got q1) b ? and c? and if u got it help m ???
11 years ago